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(-4x^2+7x+16)=0
We get rid of parentheses
-4x^2+7x+16=0
a = -4; b = 7; c = +16;
Δ = b2-4ac
Δ = 72-4·(-4)·16
Δ = 305
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{305}}{2*-4}=\frac{-7-\sqrt{305}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{305}}{2*-4}=\frac{-7+\sqrt{305}}{-8} $
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